A fighter plane, flying horizontally with a speed 360   km / h at an altitude of 500   m drops a bomb for a target straight ahead of it on the ground. The bomb should be dropped at what approximate distance ahead of the target? Assume that acceleration due to gravity g is 10   ms - 2 . Also, neglect air drag.

Step-by-step solution

Given, speed of fighter plane, v = 360   km / h = 360 × 5 18   m / s = 100   m / s Altitude, h = 500   m Now, from equation of motion, h = u t + 1 2 g t 2 ⇒    500 = 0 t + 1 2 × 10 × t 2    ∵ u = 0   and   g = 10   m / s 2 ⇒    t 2 = 100 ⇒ t = 10   s ∴ The bomb should be dropped at the distance, x = v t = 100 × 10 = 1000   m