A projectile is thrown with an initial velocity of v = a i ^ + b j ^ . If the range of projectile is double the maximum height reached by it. Find the ratio b a .

Step-by-step solution

Angle of projection, θ = tan - 1   ν y v x = tan - 1 b a ∴   tan   θ = b a   . . . i From formula: R = 4 H   cot   θ = 2 H ⇒ c o t   θ = 1 2 ∴ tan   θ = 2   As   R = 2 H   given   . . . ii From equation i and ii ,   b = 2 a b a = 2