A body of mass m thrown up vertically with velocity v₁ reaches a maximum height h₁ in t₁ seconds. Another body of mass 2 ~m is projected with a velocity v₂ at an angle . The second body reaches a maximum height h₂ in time t₂ seconds. If t₁=2 t₂ , then ratio ( h₁ h₂ ) is

Step-by-step solution

Maximum vertical height attained by body thrown with velocity v₁ h₁= v₁^2 2 g Another body of mass 2 ~m is projected with a velocity v₂ at an angle . Height attained (h₂ )= v₂^2 ^2 2 g h₁ h₂ = v₁^2 v₂^2 ^2 But t₁=2 t₂ V₂ g =2 [ V₂ g ] v₁=2 v₂ h₁ h₂ = ( 2 1 )^2= 4 1