A plane is inclined at an angle α = 30 ° with respect to the horizontal. A particle is projected with a speed u = 2   m   s - 1 , from the base of the plane, making an angle θ = 15 ° with respect to the plane as shown in the figure. The distance from the base, at which the particle hits the plane is close to [Take, g = 10   m   s - 2 ]

Step-by-step solution

The given projectile is projected at an angle θ with an inclined plane making angle α with the horizontal. The net horizontal displacement of the particle as R = u x T + 1 2 a x T 2               . . . 1 where, T = time of flight. Using formula for time of flight using a coordinate axis along the plane, we have T = 2 u y a y = 2 u sin θ g cos α           . . . 2 From equation 1 and 2 , we have the range up the inclined plane is R = u co