If a stone is to hit at a point which is at a horizontal distance 100 m away and at a height 50 m above the point from where the stone starts, then what is the value of initial speed u if the stone is launched at an angle 45 ° ?

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Correct answer: C. 20 5 m / s

From equation of trajectory, y = x tan ⁡ θ - g x 2 2 y 2 cos 2 ⁡ θ ⇒ 50 = 100 tan ⁡ 4 5 ° - 10 100 2 2 u 2 cos 2 ⁡ 4 5 ° ⇒ u 2 = 10 0 2 5 ⇒ u = 20 5 m / s

If a stone is to hit at a point which is at a horizontal distance 100 m away and at a height 50 m above the point from where the stone starts, then what is the value of initial speed u if the stone is launched at an angle 45 ° ?

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