99 Percentile Qs Bank for JEE MainPhysicsMotion in Two Dimensions
A ball is projected with a velocity u at a right angle to the inclined plane which is inclined at an angle α with the horizontal. The distance x along the inclined plane that it will travel before again striking the slope is
Options
- A2 u 2 g tan α cos α
- B2 u 2 g tan α
- C2 u 2 g cos α
- D2 u 2 g tan α sin α
Correct answer
A. 2 u 2 g tan α cos α
Step-by-step solution
It is given that a ball is projected perpendicular to an inclined plane. u = Initial velocity α = Angle of elevation of the slope Acceleration due to gravity is vertically downward, and can be resolved into a perpendicular component and a parallel component to the plane as g cos α and g sin α . Equation of motion perpendicular to the incline is ⇒ y = u t - 1 2 g cos α t 2 Upon striking the plane, the net displacement perpendicular to the incline is zero, i.e, y = 0 . ⇒ t = 2 u g cos