A particle is projected from a stationary trolley. After projection, the trolley moves with a velocity 2 15   m   s - 1 . For an observer on the trolley, the direction of the particle is as shown in .the figure while for the observer on the ground, the ball rises vertically. The maximum height reached by the ball from the trolley is h meter. The value of h will be ______.

Step-by-step solution

Given that Velocity of trolley u = 2 15   m   s - 1 . For an observer on the ground, the ball rises vertically So velocity of ball in horizontal direction will be zero with respect ground. v x = 0 ⇒ v cos 60 ° - u = 0 ⇒ v cos 60 ° = 2 15   ⇒ v = 4 15   m   s - 1 Vertical component of velocity of ball ∴ v y = v sin 60 ° = 4 15 3 2 = 2 45   ms - 1 Maximum height of ball from ground is H max = v y 2 2 g = 4 × 45 20 = 9   m