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99 Percentile Qs Bank for JEE MainPhysicsMotion in Two Dimensions

A ball is thrown at 30^ with horizontal, from the top of roof 20 ~m high with a speed of 13 ~ms ⁻¹ . At what distance from the throwing point will the ball, once again be at a height of 20 ~m from the ground? (g=10 ~ms ⁻² )

Options

  1. A10.2 ~m
  2. B14.6 ~m
  3. C18.6 ~m
  4. D9.8 ~m

Correct answer

B. 14.6 ~m

Step-by-step solution

The situation is as shown below. Given, =30^ , initial speed, u=13 ~ms ⁻¹ aligned Range & = u^2 2 g & = (13)^2 60^ 10 = 169 3 10 2 =14.6 ~m aligned Range, R=14.6 ~m Hence, the ball once again be at a height of 20 ~m from the ground at 14.6 ~m from the point of projection.

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