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A thin glass prism of μ = 1.5 is immersed in water of μ = 1.33 . The ratio of deviation of the ray in water to that in air for the same prism is

Options

  1. A1 : 4
  2. B1 : 2
  3. C1 : 8
  4. D1 : 3

Correct answer

A. 1 : 4

Step-by-step solution

In air δ = 1.5 - 1 A = A 2 In water δ = μ g μ w - 1 A = 1.5 1.33 - 1 A = A 8 δ in water δ in air = 1 4 We know that, δ in air = a μ g - 1 A and δ in water = w μ g - 1 A . δ w δ a = μ g μ w - 1 μ 9 - 1 δ w δ a = 3 2 4 3 - 1 3 2 - 1 δ w δ a = 9 8 - 1 3 2 - 1 δ w δ a = 1 8 1 2 = 1 4

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