99 Percentile Qs Bank for JEE MainPhysicsRay Optics
A point source of light B placed at a distance L in front of the centre of a mirror of width d hung vertically on a wall. A man walks in front of the mirror along a line parallel to the mirror at a distance 2 L from it as shown in figure. The greatest distance over which he can see the image of the light source in the mirror is :
Options
- A3 d
- B2 d
- Cd
- Dd 2
Correct answer
A. 3 d
Step-by-step solution
Consider the ray diagram of the situation given in the problem, we get H I = A S = d D B = C D = d 2 Since, Since, A H = 2 A D ∴     G H = 2 C D = 2 d 2 = d Similarly, I J = d ∴     G J = G H + H I + I J = d + d + d = 3 d