Light of wavelength 300   nm in medium A enters into medium B through a plane surface. If the frequency of light is 5 × 10 14   Hz and the ratio of speed in medium A to that is medium B is 4 5 , the absolute refractive index of medium B is,

Step-by-step solution

Absolute refractive index of medium A, μ A = c ν A λ = 3 × 10 8 5 × 10 14 × 300 × 10 - 9 = 2 Refractive index is inversely proportional to the velocity of light. ⇒ μ B μ A = v A v B = 4 5 ⇒ μ B = μ A 4 5 = 8 5 ⇒ μ B = 1 . 6