In Young's double slit interference experiment the wavelength of light used is 6000 Ã… . If the path difference between waves reaching a point P on the screen is 1.5 microns, then at that point P .

Step-by-step solution

aligned & =6000 Ã…, x=1.5 & =6 10⁻⁷ ~m ,=1.5 10⁻⁶ ~m aligned Path difference for maxima aligned x & =n 1.5 10⁻⁶ & =n 6 10⁻⁷ n & = 1.5 10⁻⁶ 6 10⁻⁷ = 15 6 =2.5= 5 2 aligned Value of n is always an integer for maxima, so point P is not a maxima. For maxima aligned x & =(2 n+1) 2 1.5 10⁻⁶ & =(2 n+1) 6 10⁻⁷ 2 aligned aligned (2 n+1) & = 1.5 10⁻⁶ 2 6 10⁻⁷ 2 n & =5-1 2 n & =4 n=2 aligned So, at P third dark band occurs.