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The angular deviation of 5 th order dark fringe is 12^ in a single slit experiment. If the width of the slit is 9 m then the wavelength of the incident light is

Options

  1. A4862 Å
  2. B5892 Å
  3. C6002 Å
  4. D3768 Å

Correct answer

D. 3768 Å

Step-by-step solution

Given, angular deviation of 5th order dark fringe, =12^ , Width of the slit, d=9 m Now, angular deviation of n th fringe =n d aligned 12 180 & =5 9 10⁻⁶ & or = 12 180 9 10⁻⁶ 5 ~m & or =3768 Å aligned So, the wave length of incident light is =3768 Å .

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