99 Percentile Qs Bank for JEE MainPhysicsWave Optics
Two slits separated by 0.5 ~mm are illuminated by light of wavelength 500 ~nm . The screen is at a distance of 120 ~cm from the slits. The phase difference between the interfering waves at a point 3 ~mm on the screen from the central bright fringe is ........... .
Options
- A5
- B3
- C7
Correct answer
A. 5
Step-by-step solution
Given, aligned & d =0.5 10⁻⁹ ~m and =3 10⁻³ ~mm & =500 10⁻⁹ ~m & D=120 ~cm =120 10⁻² ~m & = x D d aligned x= d D x= 3 10⁻³ 0.5 10⁻³ 1.2 = 5 4 10⁻⁶ = 2 1.25 10⁻⁶ 500 10⁻⁹ =5