In Young's double slit experiment the intensity at a point on the screen is K , where path difference is . What will be the intensity at the point where path difference is 4 ?

Step-by-step solution

I=2 I₀(1+ ) = 2 x , where x is the path as difference. K=2 I₀ (1+ ( 2 ) )=4 I₀ Now, for path difference 4 aligned & K^ =2 I₀ (1+ ( 2 4 ) )=2 I₀ & K^ = K 2 aligned