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A wire vibrates at a fundamental frequency of 500 ~Hz . A second identical wire produces 5 beats per second with it when the tension in the first wire is slightly decreased. The ratio of the tension in the second wire to the tension in the first wire is approximately equal to

Options

  1. A1.04
  2. B1.01
  3. C1.05
  4. D1.02

Correct answer

D. 1.02

Step-by-step solution

(d) Given that, fundamental frequency of first wire, f₁=500 ~Hz Let frequency of 2 nd wire be f₂ . Beat frequency, f_b=5 aligned & f_b=f₂-f₁ & f₂=f_b+f₁=500+5=505 ~Hz aligned Using, expression for fundamental frequency of wire, aligned f & = 1 2 L T f T f₂ f₁ & = T₂ T₁ 505 500 = T₂ T₁ T₂ T₁ & = ( 505 500 )^2=1.02 aligned

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