An organ pipe with both ends open has a length L=25 ~cm . An extra hole is created at position L 2 . The lowest frequency of sound produced is (assume, speed of sound =340 ~m / s )

Step-by-step solution

We know that, there must be an antinode at the open end. Since, a hole has been made at the position L 2 , so there must be another antinode at x= L 2 . For lowest frequency, =L=25 ~cm Frequency of sound produced, f= v = 340 0.25 =1360 ~Hz