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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Physics and Mathematics

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Physics and Mathematics

Given the vectors A = 2 i + 3 j + 4 k and B = 4 i + 3 j + 2 k ,...

Given the vectors A⃗=2i^+3j^+4k^\vec{A} = 2\hat{i} + 3\hat{j} + 4\hat{k} and B⃗=4i^+3j^+2k^\vec{B} = 4\hat{i} + 3\hat{j} + 2\hat{k}, determine the cross product A⃗×B⃗\vec{A} \times \vec{B}.

Options

  1. A6i^+12j^+6k^6\hat{i} + 12\hat{j} + 6\hat{k}
  2. B6i^−12j^+6k^6\hat{i} - 12\hat{j} + 6\hat{k}
  3. C−6i^+12j^−6k^-6\hat{i} + 12\hat{j} - 6\hat{k}
  4. D−6i^−12j^−6k^-6\hat{i} - 12\hat{j} - 6\hat{k}

Correct answer

C. −6i^+12j^−6k^-6\hat{i} + 12\hat{j} - 6\hat{k}

Step-by-step solution

The cross product of two vectors A⃗\vec{A} and B⃗\vec{B} is given by the determinant of their components:

A⃗×B⃗=∣i^ and j^ and k^2 and 3 and 44 and 3 and 2∣\vec{A} \times \vec{B} = \begin{vmatrix} \hat{i} \text{ and } \hat{j} \text{ and } \hat{k} \\ 2 \text{ and } 3 \text{ and } 4 \\ 4 \text{ and } 3 \text{ and } 2 \end{vmatrix}

Expanding the determinant along the first row:

A⃗×B⃗=i^(3×2−4×3)−j^(2×2−4×4)+k^(2×3−3×4)\vec{A} \times \vec{B} = \hat{i}(3 \times 2 - 4 \times 3) - \hat{j}(2 \times 2 - 4 \times 4) + \hat{k}(2 \times 3 - 3 \times 4)

A⃗×B⃗=i^(6−12)−j^(4−16)+k^(6−12)\vec{A} \times \vec{B} = \hat{i}(6 - 12) - \hat{j}(4 - 16) + \hat{k}(6 - 12)

A⃗×B⃗=−6i^+12j^−6k^\vec{A} \times \vec{B} = -6\hat{i} + 12\hat{j} - 6\hat{k}
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