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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Physics and Mathematics

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Physics and Mathematics

In a charging R – C circuit, the electric current is given by i =...

In a charging RR–CC circuit, the electric current is given by i=i0e−t/RCi = i_0 e^{-t/RC}, where i0i_0, RR, and CC are constant parameters of the circuit and tt represents time. Determine the rate of change of current at t=RCt = RC.

Options

  1. A−i0eRC-\dfrac{i_0 e}{RC}
  2. B−i0RCe-\dfrac{i_0}{RCe}
  3. Ci0RCe\dfrac{i_0}{RCe}
  4. D−i0RC-\dfrac{i_0}{RC}

Correct answer

B. −i0RCe-\dfrac{i_0}{RCe}

Step-by-step solution

Given the electric current i=i0e−t/RCi = i_0 e^{-t/RC}.

The rate of change of current is given by didt\dfrac{di}{dt}.

Differentiating ii with respect to tt gives:

didt=ddt(i0e−t/RC)=−i0RCe−t/RC\dfrac{di}{dt} = \dfrac{d}{dt} (i_0 e^{-t/RC}) = -\dfrac{i_0}{RC} e^{-t/RC}

Substituting t=RCt = RC into the expression:

didt=−i0RCe−RC/RC=−i0RCe−1=−i0RCe\dfrac{di}{dt} = -\dfrac{i_0}{RC} e^{-RC/RC} = -\dfrac{i_0}{RC} e^{-1} = -\dfrac{i_0}{RCe}
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