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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Rest and Motion Kinematics

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Rest and Motion Kinematics

A particle begins at the origin, travels along the X-axis to the...

A particle begins at the origin, travels along the X-axis to the point (20 m,0)(20 \text{ m}, 0), and subsequently returns along the same line to the point (−20 m,0)(-20 \text{ m}, 0). Determine the distance and displacement of the particle for this trip.

Options

  1. A40 m40 \text{ m} and −20 m-20 \text{ m}
  2. B60 m60 \text{ m} and −20 m-20 \text{ m}
  3. C40 m40 \text{ m} and 0 m0 \text{ m}
  4. D60 m60 \text{ m} and 20 m20 \text{ m}

Correct answer

B. 60 m60 \text{ m} and −20 m-20 \text{ m}

Step-by-step solution

Distance is the total path length covered by the particle.

The particle travels from x=0x = 0 to x=20 mx = 20 \text{ m}, covering a distance of 20 m20 \text{ m}.

It then travels from x=20 mx = 20 \text{ m} to x=−20 mx = -20 \text{ m}, covering a distance of ∣−20−20∣=40 m|-20 - 20| = 40 \text{ m}.

Total distance =20 m+40 m=60 m= 20 \text{ m} + 40 \text{ m} = 60 \text{ m}.

Displacement is the change in position of the particle.

Initial position, xi=0 mx_i = 0 \text{ m}.

Final position, xf=−20 mx_f = -20 \text{ m}.

Displacement =xf−xi=−20 m−0 m=−20 m= x_f - x_i = -20 \text{ m} - 0 \text{ m} = -20 \text{ m}.
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