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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Rest and Motion Kinematics

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Rest and Motion Kinematics

The distance from Patna to Ranchi is 260 km by air and 320 km by...

The distance from Patna to Ranchi is 260 km260 \text{ km} by air and 320 km320 \text{ km} by road. An aeroplane requires 3030 minutes to travel from Patna to Ranchi, while a delux bus takes 88 hours. Determine the average velocity of the plane.

Options

  1. A260 km/h260 \text{ km/h} from Patna to Ranchi
  2. B640 km/h640 \text{ km/h} from Patna to Ranchi
  3. C520 km/h520 \text{ km/h} from Ranchi to Patna
  4. D520 km/h520 \text{ km/h} from Patna to Ranchi

Correct answer

D. 520 km/h520 \text{ km/h} from Patna to Ranchi

Step-by-step solution

Displacement of the aeroplane is the straight line distance between Patna and Ranchi, which is 260 km260 \text{ km}.

Time taken by the aeroplane, t=30 minutes=12 ht = 30 \text{ minutes} = \dfrac{1}{2} \text{ h}.

Average velocity is defined as the ratio of displacement to time taken.

Average velocity =Displacementt=26012=520 km/h= \dfrac{\text{Displacement}}{t} = \dfrac{260}{\dfrac{1}{2}} = 520 \text{ km/h}.

The direction of average velocity is along the displacement, which is from Patna to Ranchi.
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