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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
The Forces

Concepts Of Physics MCQ Edition [Volume 1] · Physics · The Forces

A monkey is perched on a tree limb. The limb applies a normal force...

A monkey is perched on a tree limb. The limb applies a normal force of 48 N48 \text{ N} and a frictional force of 20 N20 \text{ N}. Determine the magnitude of the total force exerted by the limb on the monkey.

Options

  1. A68 N68 \text{ N}
  2. B52 N52 \text{ N}
  3. C28 N28 \text{ N}
  4. D43.6 N43.6 \text{ N}

Correct answer

B. 52 N52 \text{ N}

Step-by-step solution

The total force exerted by the limb on the monkey is the resultant of the normal force and the frictional force.

Since the normal force and frictional force are perpendicular to each other, the magnitude of the total force FF is given by:

F=N2+f2F = \sqrt{N^2 + f^2}

Substituting the given values N=48 NN = 48 \text{ N} and f=20 Nf = 20 \text{ N}:

F=482+202F = \sqrt{48^2 + 20^2}

F=2304+400F = \sqrt{2304 + 400}

F=2704=52 NF = \sqrt{2704} = 52 \text{ N}
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