As depicted in the figure, the heights of the mercury surfaces in...

From the given figure, the mercury level in the open arm is higher than that in the arm connected to the gas cylinder. This indicates that the gas pressure is greater than the atmospheric pressure.

The difference in the height of the mercury levels is:
$h = 8 \text{ cm} - 2 \text{ cm} = 6 \text{ cm} = 0.06 \text{ m}$

The gauge pressure of the gas is given by:
$\Delta P = \rho g h$
Substituting the standard values for the density of mercury ($\rho = 13.6 \times 10^3 \text{ kg m}^{-3}$) and acceleration due to gravity ($g = 9.8 \text{ m s}^{-2}$):
$\Delta P = 13.6 \times 10^3 \times 9.8 \times 0.06$
$\Delta P = 7996.8 \text{ N m}^{-2} \approx 0.08 \times 10^5 \text{ N m}^{-2}$

The absolute pressure of the enclosed gas is:
$P_{\text{gas}} = P_{\text{atm}} + \Delta P$
$P_{\text{gas}} = 1.01 \times 10^5 + 0.08 \times 10^5$
$P_{\text{gas}} = 1.09 \times 10^5 \text{ N m}^{-2}$

Answer: $1.09 \times 10^5 \text{ N m}^{-2}$