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AP EAMCET201921 Apr 2019Evening ShiftChemistryChemical EquilibriumActual

The value of K C for the equilibrium reaction: CO 2 ( g ) + C ( s ) ⇌ 2 CO ( g ) at T ( K ) is 0 . 036 . If the equilibrium concentration of CO 2 ( g ) is 0 . 004 M , the concentration of CO ( g ) in molL - 1 is

Options

  1. A3 . 6 × 10 - 2
  2. B2 . 0 × 10 - 2
  3. C1 . 2 × 10 - 2
  4. D1 . 2 × 10 - 3

Correct answer

C. 1 . 2 × 10 - 2

Step-by-step solution

As equilibrium constant can be written as: K c = C O 2 C O 2 0 . 036 = C O 2 0 . 004 C O = 1 . 2 × 10 - 2

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