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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Light Waves

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Light Waves

For light of wavelength 400 nm , the index of refraction of fused...

For light of wavelength 400 nm400 \text{ nm}, the index of refraction of fused quartz is 1.4721.472, and for light of wavelength 760 nm760 \text{ nm}, it is 1.4521.452. Determine the speeds of light for these wavelengths in fused quartz.

Options

  1. A4.42×108 m s−14.42 \times 10^8 \text{ m s}^{-1}, 4.36×108 m s−14.36 \times 10^8 \text{ m s}^{-1}
  2. B2.04×108 m s−12.04 \times 10^8 \text{ m s}^{-1}, 2.07×108 m s−12.07 \times 10^8 \text{ m s}^{-1}
  3. C2.07×108 m s−12.07 \times 10^8 \text{ m s}^{-1}, 2.04×108 m s−12.04 \times 10^8 \text{ m s}^{-1}
  4. D2.04×105 m s−12.04 \times 10^5 \text{ m s}^{-1}, 2.07×105 m s−12.07 \times 10^5 \text{ m s}^{-1}

Correct answer

B. 2.04×108 m s−12.04 \times 10^8 \text{ m s}^{-1}, 2.07×108 m s−12.07 \times 10^8 \text{ m s}^{-1}

Step-by-step solution

The speed of light in a medium is given by v=cnv = \dfrac{c}{n}, where c=3×108 m s−1c = 3 \times 10^8 \text{ m s}^{-1} is the speed of light in vacuum and nn is the refractive index of the medium.

For light of wavelength 400 nm400 \text{ nm}, the refractive index is n1=1.472n_1 = 1.472.

v1=3×1081.472≈2.04×108 m s−1v_1 = \dfrac{3 \times 10^8}{1.472} \approx 2.04 \times 10^8 \text{ m s}^{-1}

For light of wavelength 760 nm760 \text{ nm}, the refractive index is n2=1.452n_2 = 1.452.

v2=3×1081.452≈2.07×108 m s−1v_2 = \dfrac{3 \times 10^8}{1.452} \approx 2.07 \times 10^8 \text{ m s}^{-1}
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