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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Optical Instruments

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Optical Instruments

An object is viewed using a simple microscope of focal length 12 cm...

An object is viewed using a simple microscope of focal length 12 cm12 \text{ cm}. To obtain the maximum angular magnification, at what distance from the lens should the object be positioned? The least distance for clear vision is 25 cm25 \text{ cm}.

Options

  1. A12.0 cm12.0 \text{ cm}
  2. B8.1 cm8.1 \text{ cm}
  3. C16.4 cm16.4 \text{ cm}
  4. D23.1 cm23.1 \text{ cm}

Correct answer

B. 8.1 cm8.1 \text{ cm}

Step-by-step solution

For maximum angular magnification, the final image must be formed at the least distance of distinct vision.

Given:
Focal length, f=+12 cmf = +12 \text{ cm}
Image distance, v=−D=−25 cmv = -D = -25 \text{ cm}

Using the lens formula:
1v−1u=1f\dfrac{1}{v} - \dfrac{1}{u} = \dfrac{1}{f}

1u=1v−1f\dfrac{1}{u} = \dfrac{1}{v} - \dfrac{1}{f}

1u=1−25−112\dfrac{1}{u} = \dfrac{1}{-25} - \dfrac{1}{12}

1u=−12−25300=−37300\dfrac{1}{u} = \dfrac{-12 - 25}{300} = -\dfrac{37}{300}

u=−30037 cm≈−8.1 cmu = -\dfrac{300}{37} \text{ cm} \approx -8.1 \text{ cm}

The object should be positioned at a distance of 8.1 cm8.1 \text{ cm} from the lens.
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