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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Rotational Mechanics

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Rotational Mechanics

Determine the moment of inertia of a pair of spheres, each...

Determine the moment of inertia of a pair of spheres, each possessing a mass mm and radius rr, placed in contact, about the tangent passing through their point of contact.

Options

  1. A14mr25\dfrac{14mr^2}{5}
  2. B28mr25\dfrac{28mr^2}{5}
  3. C4mr25\dfrac{4mr^2}{5}
  4. D7mr25\dfrac{7mr^2}{5}

Correct answer

A. 14mr25\dfrac{14mr^2}{5}

Step-by-step solution

The moment of inertia of a solid sphere of mass mm and radius rr about its diameter is given by Icm=25mr2I_{cm} = \dfrac{2}{5}mr^2.

The tangent passing through the point of contact of the two spheres is at a perpendicular distance rr from the center of each sphere.

Using the parallel axis theorem, the moment of inertia of one sphere about this tangent is I1=Icm+mr2=25mr2+mr2=75mr2I_1 = I_{cm} + mr^2 = \dfrac{2}{5}mr^2 + mr^2 = \dfrac{7}{5}mr^2.

Since the system consists of two identical spheres, the total moment of inertia of the pair about the common tangent is I=I1+I2=75mr2+75mr2=145mr2I = I_1 + I_2 = \dfrac{7}{5}mr^2 + \dfrac{7}{5}mr^2 = \dfrac{14}{5}mr^2.
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