A pulley of radius 10 cm and moment of inertia 0.5 kg-m^2 connects two blocks of masses 4.0 kg and 2.0 kg on inclined planes as shown. The plane beneath the 2.0 kg block has coefficient of friction 0.5 , while the plane

Correct answer: A. 0.125 m/s^2 Write the equations of motion for both blocks along their planes, include friction on the 2.0 kg block, and use = Iα for the pulley with α = a/r . Solving the coupled equations gives a = 0.125 m/s^2 for the 4.0 kg block.

Concepts Of Physics MCQ Edition [Volume 1]

Exam: Concepts Of Physics MCQ Edition [Volume 1]
Subject: Physics
Chapter: Rotational Mechanics

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Rotational Mechanics

A pulley of radius 10 cm and moment of inertia 0.5 kg-m^2 connects...

A pulley of radius

10 \text{ cm}

and moment of inertia

0.5 \text{ kg-m}^2

connects two blocks of masses

4.0 \text{ kg}

and

2.0 \text{ kg}

on inclined planes as shown. The plane beneath the

2.0 \text{ kg}

block has coefficient of friction

0.5

, while the plane beneath the

4.0 \text{ kg}

block is frictionless. Find the acceleration of the

4.0 \text{ kg}

block.

Options

A $0.125 \text{ m/s}^2$
B $0.25 \text{ m/s}^2$
C $0.0625 \text{ m/s}^2$
D $0.50 \text{ m/s}^2$

Correct answer

A. $0.125 \text{ m/s}^2$

Step-by-step solution

Write the equations of motion for both blocks along their planes, include friction on the

2.0 \text{ kg}

block, and use

\tau = I\alpha

for the pulley with

\alpha = a/r

. Solving the coupled equations gives

a = 0.125 \text{ m/s}^2

for the

4.0 \text{ kg}

block.

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