Concepts Of Physics MCQ Edition [Volume 1]PhysicsRotational Mechanics
A diver with a moment of inertia of 6.0 kg-m ^2 about an axis passing through his centre of mass rotates about this axis at an angular speed of 2 rad/s . If the diver folds his hands and feet, reducing the moment of inertia to 5.0 kg-m ^2 , what will be the new angular speed?
Options
- A1.2 rad/s
- B2.4 rad/s
- C1.67 rad/s
- D4.8 rad/s
Correct answer
B. 2.4 rad/s
Step-by-step solution
According to the principle of conservation of angular momentum, if no external torque acts on a system, its total angular momentum remains constant. Initial angular momentum L₁ = I₁ ₁ Final angular momentum L₂ = I₂ ₂ Equating the initial and final angular momentum: I₁ ₁ = I₂ ₂ Substituting the given values: 6.0 2 = 5.0 ₂ ₂ = 12.0 5.0 = 2.4 rad/s