Concepts Of Physics MCQ Edition [Volume 1]PhysicsRotational Mechanics
A uniform rod of length L and mass M lies on a smooth horizontal table. A particle of mass m moving on the table strikes the rod perpendicularly at one end with speed v and sticks to it. (a) Find the velocity of the centre of mass C of the system "rod + particle". (b) Find the velocity of the particle with respect to C before the collision. (c) Find the velocity of the rod with respect to C before the collision. (d)
Options
- A(a) mv M + m (b) Mv M + m (c) - mv M + m (d) M^2 m v L 2(M + m)^2 , M m^2 v L 2(M + m)^2 (e) M(M + 4m)L^2 12(M
- B(a) mv M + m (b) Mv M + m (c) - mv M + m (d) M^2 m v L (M + m)^2 , M m^2 v L (M + m)^2 (e) M(M + 2m)L^2 12(M +
- C(a) mv M + m (b) mv M + m (c) - Mv M + m (d) M m v L (M + m)^2 , M m v L (M + m)^2 (e) (M + m)L^2 12 (f) mv M
- D(a) mv M (b) v (c) 0 (d) 0 , 0 (e) ML^2 12 (f) mv M , 0
Correct answer
A. (a) mv M + m (b) Mv M + m (c) - mv M + m (d) M^2 m v L 2(M + m)^2 , M m^2 v L 2(M + m)^2 (e) M(M + 4m)L^2 12(M
Step-by-step solution
(a) mv M + m (b) Mv M + m (c) - mv M + m (d) M^2 mvl 2(M + m)^2 , Mm^2 vl 2(M + m)^2 (e) M(M + 4m)L^2 12(M + m) (f) mv M + m , 6mv (M + 4m)L