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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Rotational Mechanics

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Rotational Mechanics

A cylinder is rolling on a horizontal plane surface. Given that the...

A cylinder is rolling on a horizontal plane surface. Given that the speed of its centre is 25 m/s25 \text{ m/s}, determine the speed of its highest point.

Options

  1. A50 m/s50 \text{ m/s}
  2. B25 m/s25 \text{ m/s}
  3. C252 m/s25\sqrt{2} \text{ m/s}
  4. D0 m/s0 \text{ m/s}

Correct answer

A. 50 m/s50 \text{ m/s}

Step-by-step solution

For a cylinder rolling on a horizontal surface, the condition for pure rolling is vcm=ωRv_{cm} = \omega R.

The velocity of the highest point is the vector sum of the translational velocity of the centre of mass and the tangential velocity due to rotation.

At the highest point, both velocities are in the same direction.

vtop=vcm+ωR=2vcmv_{top} = v_{cm} + \omega R = 2v_{cm}

Given vcm=25 m/sv_{cm} = 25 \text{ m/s}, substituting the value:

vtop=2×25=50 m/sv_{top} = 2 \times 25 = 50 \text{ m/s}
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