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JEE Main 20266 AprilMorning Shift
Exam
JEE Main
Year
2026
Date
6 April
Shift
Morning Shift
Subject
Chemistry
Chapter
Hydrocarbons

JEE Main 2026 · 6 April · Morning Shift · Chemistry · Hydrocarbons

Given below are two statements: Statement I: Methane can be...

Given below are two statements:

Statement I: Methane can be prepared by decarboxylation of sodium ethanoate, Kolbe's electrolysis of sodium acetate and reaction of CH3MgBr\text{CH}_3\text{MgBr} with water.

Statement II: Methane cannot be prepared from unsaturated hydrocarbons and by Wurtz reaction.

In the light of the above statements, choose the correct answer from the options given below

Options

  1. ABoth Statement I and Statement II are true
  2. BBoth Statement I and Statement II are false
  3. CStatement I is true but Statement II is false
  4. DStatement I is false but Statement II is true

Correct answer

D. Statement I is false but Statement II is true

Step-by-step solution

Statement I is false because Kolbe's electrolysis of sodium acetate produces ethane, not methane. The reaction is: 2CH3COONa+2H2O→ElectrolysisCH3−CH3+2CO2+H2+2NaOH2\text{CH}_3\text{COONa} + 2\text{H}_2\text{O} \xrightarrow{\text{Electrolysis}} \text{CH}_3-\text{CH}_3 + 2\text{CO}_2 + \text{H}_2 + 2\text{NaOH}. Decarboxylation of sodium ethanoate and the reaction of CH3MgBr\text{CH}_3\text{MgBr} with water do produce methane.

Statement II is true because the simplest unsaturated hydrocarbon is ethene (C2H4\text{C}_2\text{H}_4), which upon hydrogenation yields ethane, meaning methane cannot be prepared from unsaturated hydrocarbons. Additionally, the Wurtz reaction involves the coupling of two alkyl halide molecules to form an alkane with at least two carbon atoms (2RX+2Na→R−R+2NaX2\text{RX} + 2\text{Na} \rightarrow \text{R}-\text{R} + 2\text{NaX}), so methane cannot be prepared by this method.

Therefore, Statement I is false but Statement II is true.

Answer: Statement I is false but Statement II is true
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