AP EAMCET201825 Apr 2018Morning ShiftChemistryChemical EquilibriumActual
For the gaseous reactions ( I ) and ( II ) , the equilibriun constants are X and Y , respectively. I . 1 2 N 2 g + O 2 g ⇌ NO 2 g II . 2 NO 2 g ⇌ N 2 O 4 g Using the above reactions the equilibrium constant Z for the reaction ( III ) given below is III . N 2 O 4 g ⇌ N 2 g + 2 O 2 g
Options
- AZ = XY
- BZ = Y 2 X
- CZ = 1 XY 2
- DZ = 1 X 2 Y
Correct answer
D. Z = 1 X 2 Y
Step-by-step solution
For the gaseous reactions ( I ) and ( II ) , the equilibrium constants are X and Y , respectively. I . 1 2 N 2   g + O 2   g ⇌ NO 2   g .........( 1 ) II .   2 NO 2   g ⇌ N 2 O 4   g .........( 2 ) the equilibrium constant Z for the reaction ( III ) III .   N 2 O 4   g ⇌ N 2   g + 2 O 2   g ........( 3 ) Eq ( 3 ) = -   Eq ( 1 ) × 2   + Eq 2 Thus , Z = 1 X 2 Y .