A load of 10 kg is suspended by a metal wire that is 3 m long and possesses a cross-sectional area of 4 mm ^2 . Determine the stress. The Young modulus of the metal is 2.0 10¹¹ N/m ^2 .

Step-by-step solution

Given mass of the load, m = 10 kg Cross-sectional area, A = 4 mm ^2 = 4 10⁻⁶ m ^2 Acceleration due to gravity, g = 9.8 m/s ^2 The restoring force developed in the wire is equal to the weight of the suspended load. F = mg = 10 9.8 = 98 N Stress is defined as the restoring force per unit area. Stress = F A Stress = 98 4 10⁻⁶ = 24.5 10^6 N/m ^2 Stress = 2.45 10^7 N/m ^2