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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Some Mechanical Properties of Matter

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Some Mechanical Properties of Matter

A steel wire and a copper wire, both possessing equal length and...

A steel wire and a copper wire, both possessing equal length and equal cross-sectional area, are joined end to end and the combination is subjected to a tension. Determine the ratio of the stress developed in the steel wire to the stress developed in the copper wire. Let YY of steel =2×1011 N/m2= 2 \times 10^{11} \text{ N/m}^2 and YY of copper =1.3×1011 N/m2= 1.3 \times 10^{11} \text{ N/m}^2.

Options

  1. A11
  2. B1320\dfrac{13}{20}
  3. C400169\dfrac{400}{169}
  4. D2013\dfrac{20}{13}

Correct answer

A. 11

Step-by-step solution

Stress is defined as the internal restoring force per unit area.

When the wires are joined end to end and subjected to a tension, they are in a series combination. Therefore, the same force FF acts on both the steel and copper wires.

It is given that both wires have the same cross-sectional area AA.

The stress in the steel wire is σs=FA\sigma_{s} = \dfrac{F}{A}.

The stress in the copper wire is σc=FA\sigma_{c} = \dfrac{F}{A}.

The ratio of the stress developed in the steel wire to that in the copper wire is σsσc=F/AF/A=1\dfrac{\sigma_{s}}{\sigma_{c}} = \dfrac{F/A}{F/A} = 1.
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