A sound wave having a frequency of 100 Hz is travelling in air. The speed of sound in air is 350 m s^ -1 . By how much does the phase change at a given point in 2.5 ms ?

Question

Quantrex Academy · Accepted Answer

Correct answer: A. (π)/(2)

The phase of a wave at a fixed position

x

as a function of time

t

is given by

\phi = \omega t - kx + \phi_0

.

The change in phase at a given point over a time interval

\Delta t

is given by:

\Delta \phi = \omega \Delta t = 2\pi f \Delta t

Given frequency

f = 100 \text{ Hz}

and time interval

\Delta t = 2.5 \text{ ms} = 2.5 \times 10^{-3} \text{ s}

.

Substituting the values:

\Delta \phi = 2\pi \times 100 \times 2.5 \times 10^{-3}

\Delta \phi = 2\pi \times 0.25

\Delta \phi = \dfrac{\pi}{2}

A sound wave having a frequency of 100 Hz is travelling in air. The...

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