A sound wave having a frequency of 100 Hz is travelling in air. The speed of sound in air is 350 m s ⁻¹ . What is the phase difference at a given instant between two points separated by a distance of 10.0 cm along the direction of propagation?

Step-by-step solution

Given frequency f = 100 Hz and speed of sound v = 350 m s ⁻¹ . The wavelength of the sound wave is given by: = v f = 350 100 = 3.5 m The phase difference between two points separated by a distance x is: = 2 x Given x = 10.0 cm = 0.1 m . Substituting the values: = 2 3.5 0.1 = 0.2 3.5 = 2 35