If the sound level within a room is raised from 50 dB to 60 dB , by what factor does the pressure amplitude increase?

Step-by-step solution

The sound level in decibels is given by = 10 ₁₀ ( I I₀ ) The difference in sound level is = 60 - 50 = 10 dB ₂ - ₁ = 10 ₁₀ ( I₂ I₁ ) 10 = 10 ₁₀ ( I₂ I₁ ) I₂ I₁ = 10 The intensity of a sound wave is directly proportional to the square of its pressure amplitude, I P₀^2 ( P₀₂ P₀₁ )^2 = I₂ I₁ = 10 P₀₂ P₀₁ = 10