Determine the fundamental frequency of vibration for an open organ pipe measuring 5 cm in length. Assume the speed of sound in air is 340 m s^ -1 .

Correct answer: C. 3.4 kHz For an open organ pipe, the fundamental frequency is given by: f = (v)/(2L) Given v = 340 m s^ -1 and L = 5 cm = 0.05 m . Substituting the values: f = (340)/(2 × 0.05) f = (340)/(0.1) f = 3400 Hz = 3.4 kHz

Concepts Of Physics MCQ Edition [Volume 1]

Exam: Concepts Of Physics MCQ Edition [Volume 1]
Subject: Physics
Chapter: Sound Waves

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Sound Waves

Determine the fundamental frequency of vibration for an open organ...

Determine the fundamental frequency of vibration for an open organ pipe measuring

5 \text{ cm}

in length. Assume the speed of sound in air is

340 \text{ m s}^{-1}

Options

A $6.8 \text{ kHz}$
B $34 \text{ kHz}$
C $3.4 \text{ kHz}$
D $1.7 \text{ kHz}$

Correct answer

C. $3.4 \text{ kHz}$

Step-by-step solution

For an open organ pipe, the fundamental frequency is given by:

f = \dfrac{v}{2L}

Given

v = 340 \text{ m s}^{-1}

and

L = 5 \text{ cm} = 0.05 \text{ m}

.

Substituting the values:

f = \dfrac{340}{2 \times 0.05}

f = \dfrac{340}{0.1}

f = 3400 \text{ Hz} = 3.4 \text{ kHz}

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