At T( ~K ) , the equilibrium constant of H ₂( ~g )+ I ₂( ~g ) 2 HI ( g ) is 49 . If [ H ₂ ], [ I ₂ ] at equilibrium at the same temperature are 2.0 10⁻² M and 8.0 10⁻² M respectively, the [HI] at equilibrium in mol L ⁻¹ is

Step-by-step solution

Given, aligned & K_C=49 & [ H ₂ ]=2.0 10⁻² M & [ I ₂ ]=8.0 10⁻² M aligned For, the reaction, aligned H ₂(g)+ I ₂(g) & 2 HI (g) & K_C= [ HI ]^2 [ H ₂ ] [ I ₂ ] or [ HI ]^2=K_C [ H ₂ [ I ₂ ] . aligned On putting the values in the above equation, we have aligned [ HI ]^2 & =49 16 10⁻⁴ HI & = 49 16+10⁻⁴ =0.28 ~mol aligned