A block of mass 2.00 kg travelling at a speed of 10.0 m/s accelerates at 3.00 m/s ^2 for 5.00 s . Determine its final kinetic energy.

Step-by-step solution

Given initial velocity u = 10.0 m/s , acceleration a = 3.00 m/s ^2 , and time t = 5.00 s . Using the first equation of motion, the final velocity v is: v = u + at v = 10.0 + (3.00)(5.00) = 25.0 m/s The final kinetic energy K is given by: K = 1 2 mv^2 K = 1 2 (2.00)(25.0)^2 K = 625 J