A stationary particle of mass 15 g is accelerated by a constant force of 2.50 N over a displacement of 2.50 m . Determine the work done and the average power delivered.

Step-by-step solution

Work done by the constant force is given by: W = Fs = 2.50 2.50 = 6.25 J Acceleration of the particle is: a = F m = 2.50 15 10⁻³ = 500 3 m/s ^2 Using the equation of motion v^2 = u^2 + 2as with u = 0 : v^2 = 0 + 2 500 3 2.50 = 2500 3 v = 50 3 m/s For constant acceleration, the average velocity is: v_ avg = u+v 2 = 25 3 m/s Average power delivered is: P_ avg = F v_ avg = 2.50 25 3 = 62.5 3 36.1 W