At 1000 ~K , if the equilibrium constant K_p for the reaction. 2 NOCl (g) 2 NO (g)+ Cl ₂(g) is 4.157 10⁻⁴ bar, the K_C ( . in mol L ⁻¹ ) is (R=0.083 ~L bar K ⁻¹ ~mol ⁻¹ )

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Correct answer: D. 50 10⁻⁶

K_p=K_c(R T)^ n Where, aligned & K_C and K_p= Equilibrium constants & R= Gas constant (0.083 ~L bar ⁻¹ mol ⁻¹ ) & T= Temperature (1000 ~K ) aligned n= Number of gaseous moles of product -Moles of reactant aligned K_c & =4.157 10⁻⁴ n & =3-2=1 K_C= K_b R T & = 4.157 10⁻⁴ 0.083 1000 & =5.0 10⁻⁶ aligned

At 1000 ~K , if the equilibrium constant K_p for the reaction. 2 NOCl (g) 2 NO (g)+ Cl ₂(g) is 4.157 10⁻⁴ bar, the K_C ( . in mol L ⁻¹ ) is (R=0.083 ~L bar K ⁻¹ ~mol ⁻¹ )

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