AP EAMCET201823 Apr 2018Morning ShiftChemistryChemical EquilibriumActual
For the gaseous reactions (I) and (II), the equilibrium constants are X and Y respectively. I. 1 2 ~N ₂(g)+ O ₂(g) NO ₂(g) II. 2 NO ₂(g) N ₂ O ₄(g) Using the above reactions the equilibrium constant Z for the reaction (III) given below is III. N ₂ O ₄(g) N ₂(g)+2 O ₂(g)
Options
- AZ=X Y
- BZ= Y^2 X
- CZ= 1 X Y^2
- DZ= 1 X^2 Y
Correct answer
D. Z= 1 X^2 Y
Step-by-step solution
For reaction aligned 1 2 ~N ₂(g)+ O ₂(g) & NO ₂(g) X & =K_ C₁ = [ NO ₂ ] [ N ₂ ]^ 1 / 2 [ O ₂ ] aligned aligned & For 2 NO ₂(g) N ₂ O ₄(g) & Y=K_ C₂ = [ N ₂ O ₄ ] [ NO ₂ ]^2 aligned For reaction N ₂ O ₄(g) N ₂(g)+2 O ₂ Substituting values from equation (i) and (ii) in equation (iii) we get. aligned & Z= ( [ NO ₂ ] X )^2 / Y [ NO ₂ ]^2 & Z= [ NO ₂ ]^2 X^2 Y [ NO ₂ ]^2 = 1 X^2 Y aligned