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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Rotational Mechanics

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Rotational Mechanics

Suppose A represents a unit vector directed along the axis of...

Suppose A⃗\vec{A} represents a unit vector directed along the axis of rotation of a purely rotating body, and B⃗\vec{B} is a unit vector directed along the velocity of a particle PP of the body situated away from the axis. The value of A⃗⋅B⃗\vec{A} \cdot \vec{B} is

Options

  1. A00
  2. B1/21/2
  3. C−1-1
  4. D11

Correct answer

A. 00

Step-by-step solution

For a purely rotating body, the velocity v⃗\vec{v} of any particle PP situated away from the axis of rotation is given by v⃗=ω⃗×r⃗\vec{v} = \vec{\omega} \times \vec{r}, where ω⃗\vec{\omega} is the angular velocity vector and r⃗\vec{r} is the position vector of the particle.

The angular velocity vector ω⃗\vec{\omega} is directed along the axis of rotation.

From the properties of the cross product, the velocity vector v⃗\vec{v} is perpendicular to both ω⃗\vec{\omega} and r⃗\vec{r}.

Since A⃗\vec{A} is a unit vector along the axis of rotation (parallel to ω⃗\vec{\omega})andB⃗and \vec{B} is a unit vector along the velocity v⃗\vec{v}, A⃗\vec{A} is perpendicular to B⃗\vec{B}.

A⃗⋅B⃗=∣A⃗∣∣B⃗∣cos⁡(90∘)=0\vec{A} \cdot \vec{B} = |\vec{A}| |\vec{B}| \cos(90^{{}^{{}^{\circ}}}) = 0
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