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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Rotational Mechanics

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Rotational Mechanics

A body rotates uniformly about an axis fixed in an inertial frame...

A body rotates uniformly about an axis fixed in an inertial frame of reference. Let A⃗\vec{A} be a unit vector along the rotation axis and B⃗\vec{B} be a unit vector along the resultant force acting on a particle PP of the body located away from the axis. The value of A⃗⋅B⃗\vec{A} \cdot \vec{B} is

Options

  1. A11
  2. B00
  3. C12\dfrac{1}{2}
  4. D−1-1

Correct answer

B. 00

Step-by-step solution

Since the body rotates uniformly about a fixed axis, its angular acceleration is zero.

The particle PP moves in a circular path centered on the axis of rotation. The only acceleration of the particle is the centripetal acceleration, which is directed towards the center of its circular path.

This means the resultant force F⃗\vec{F} acting on the particle is directed towards the axis and is perpendicular to the axis of rotation.

Since A⃗\vec{A} is along the axis of rotation and B⃗\vec{B} is along the resultant force, the angle between them is 90∘90^{{}^{{}^{\circ}}}.

Therefore, A⃗⋅B⃗=∣A⃗∣∣B⃗∣cos⁡90∘=0\vec{A} \cdot \vec{B} = |\vec{A}||\vec{B}|\cos 90^{{}^{{}^{\circ}}} = 0.
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