When additional air is forced into a soap bubble, the pressure...

The pressure inside a soap bubble of radius $R$ and surface tension $T$ is given by $P = P_0 + \dfrac{4T}{R}$, where $P_0$ is the atmospheric pressure.

When additional air is forced into the soap bubble, its size increases, meaning its radius $R$ increases.

Since the excess pressure $\Delta P = \dfrac{4T}{R}$ is inversely proportional to the radius, an increase in $R$ leads to a decrease in the excess pressure.

Therefore, the total pressure inside the soap bubble decreases.