The density and the bulk modulus of water are both greater than...

The velocity of sound in a fluid medium is given by the formula:

$v = \sqrt{\dfrac{B}{\rho}}$

where $B$ is the bulk modulus and $\rho$ is the density of the medium.

For water and air, the velocities are:

$v_{w} = \sqrt{\dfrac{B_{w}}{\rho_{w}}}$ and $v_{a} = \sqrt{\dfrac{B_{a}}{\rho_{a}}}$

It is given that $B_{w} > B_{a}$ and $\rho_{w} > \rho_{a}$.

Since both the numerator and the denominator for water are greater than those for air, the ratio $\dfrac{B_{w}}{\rho_{w}}$ could be greater than, less than, or equal to $\dfrac{B_{a}}{\rho_{a}}$ depending on the actual numerical values of these quantities.

Therefore, based solely on the given information, the velocity of sound in air cannot be compared to its velocity in water.