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Concepts Of Physics MCQ Edition [Volume 2]
Exam
Concepts Of Physics MCQ Edition [Volume 2]
Subject
Physics
Chapter
Electric Current in Conductors

Concepts Of Physics MCQ Edition [Volume 2] · Physics · Electric Current in Conductors

A voltmeter of resistance 400 is utilized to measure the potential...

A voltmeter of resistance 400 Ω400\text{ }\Omega is utilized to measure the potential difference across a 100 Ω100\text{ }\Omega resistor in a circuit consisting of an 84 V84\text{ V} battery connected in series with the 100 Ω100\text{ }\Omega resistor and a 200 Ω200\text{ }\Omega resistor. Calculate the potential difference across the 100 Ω100\text{ }\Omega resistor before the voltmeter is connected.
A voltmeter of resistance 400 is utilized to measure the potential difference across a 100 resistor in a circuit

Options

  1. A60 V60\text{ V}
  2. B24 V24\text{ V}
  3. C28 V28\text{ V}
  4. D56 V56\text{ V}

Correct answer

C. 28 V28\text{ V}

Step-by-step solution

Before the voltmeter is connected, the circuit consists of the 100 Ω100\text{ }\Omega and 200 Ω200\text{ }\Omega resistors in series with the 84 V84\text{ V} battery.

Total resistance of the circuit is:

Req=100+200=300 ΩR_{eq} = 100 + 200 = 300\text{ }\Omega

Current flowing through the circuit is:

I=VReq=84300 AI = \dfrac{V}{R_{eq}} = \dfrac{84}{300}\text{ A}

The potential difference across the 100 Ω100\text{ }\Omega resistor is:

V100=I×100=84300×100=28 VV_{100} = I \times 100 = \dfrac{84}{300} \times 100 = 28\text{ V}
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