Concepts Of Physics MCQ Edition [Volume 2]PhysicsElectric Current in Conductors
The voltmeter depicted in the figure measures a potential difference of 18 V across the 50 resistor. Determine the resistance of the voltmeter.
Options
- A72
- B100
- C130
- D36
Correct answer
C. 130
Step-by-step solution
Given the potential difference across the parallel combination is V_p = 18 V . The potential difference across the 24 resistor is: V₂₄ = 30 - 18 = 12 V The current in the main circuit is: I = 12 24 = 0.5 A Let R_V be the resistance of the voltmeter. The equivalent resistance of the parallel part is: R_p = 18 0.5 = 36 For the parallel combination: 1 R_p = 1 50 + 1 R_V 1 36 = 1 50 + 1 R_V 1 R_V = 1 36 - 1 50 = 25 - 18 900 = 7 900 R_V = 900 7 128.6 The closest option to this value is 130 . Answer: 130